Java整型数与网络字节序byte[]数组转换关系详解

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niminba   2021-5-23 02:50   644   0

本文实例讲述了Java整型数与网络字节序byte[]数组转换关系。分享给大家供大家参考,具体如下:

工作项目需要在java和c/c++之间进行socket通信,socket通信是以字节流或者字节包进行的,socket发送方须将数据转换为字节流或者字节包,而接收方则将字节流和字节包再转换回相应的数据类型。如果发送方和接收方都是同种语言,则一般只涉及到字节序的调整。而对于java和c/c++的通信,则情况就要复杂一些,主要是因为java中没有unsigned类型,并且java和c在某些数据类型上的长度不一致。

针对这种情况,本文整理了java数据类型和网络字节流或字节包(相当于java的byte数组)之间转换方法。实际上网上这方面的资料不少,但往往不全,甚至有些有错误,于是就花了点时间对java整型数和网络字节序的byte[]之间转换的各种情况做了一些验证和整理。整理出来的函数如下:

public class ByteConvert {
  // 以下 是整型数 和 网络字节序的 byte[] 数组之间的转换
  public static byte[] longToBytes(long n) {
    byte[] b = new byte[8];
    b[7] = (byte) (n & 0xff);
    b[6] = (byte) (n >> 8 & 0xff);
    b[5] = (byte) (n >> 16 & 0xff);
    b[4] = (byte) (n >> 24 & 0xff);
    b[3] = (byte) (n >> 32 & 0xff);
    b[2] = (byte) (n >> 40 & 0xff);
    b[1] = (byte) (n >> 48 & 0xff);
    b[0] = (byte) (n >> 56 & 0xff);
    return b;
  }
  public static void longToBytes( long n, byte[] array, int offset ){
    array[7+offset] = (byte) (n & 0xff);
    array[6+offset] = (byte) (n >> 8 & 0xff);
    array[5+offset] = (byte) (n >> 16 & 0xff);
    array[4+offset] = (byte) (n >> 24 & 0xff);
    array[3+offset] = (byte) (n >> 32 & 0xff);
    array[2+offset] = (byte) (n >> 40 & 0xff);
    array[1+offset] = (byte) (n >> 48 & 0xff);
    array[0+offset] = (byte) (n >> 56 & 0xff);
  }
  public static long bytesToLong( byte[] array )
  {
    return ((((long) array[ 0] & 0xff) << 56)
       | (((long) array[ 1] & 0xff) << 48)
       | (((long) array[ 2] & 0xff) << 40)
       | (((long) array[ 3] & 0xff) << 32)
       | (((long) array[ 4] & 0xff) << 24)
       | (((long) array[ 5] & 0xff) << 16)
       | (((long) array[ 6] & 0xff) << 8)
       | (((long) array[ 7] & 0xff) << 0));
  }
  public static long bytesToLong( byte[] array, int offset )
  {
    return ((((long) array[offset + 0] & 0xff) << 56)
       | (((long) array[offset + 1] & 0xff) << 48)
       | (((long) array[offset + 2] & 0xff) << 40)
       | (((long) array[offset + 3] & 0xff) << 32)
       | (((long) array[offset + 4] & 0xff) << 24)
       | (((long) array[offset + 5] & 0xff) << 16)
       | (((long) array[offset + 6] & 0xff) << 8)
       | (((long) array[offset + 7] & 0xff) << 0));
  }
  public static byte[] intToBytes(int n) {
    byte[] b = new byte[4];
    b[3] = (byte) (n & 0xff);
    b[2] = (byte) (n >> 8 & 0xff);
    b[1] = (byte) (n >> 16 & 0xff);
    b[0] = (byte) (n >> 24 & 0xff);
    return b;
  }
  public static void intToBytes( int n, byte[] array, int offset ){
    array[3+offset] = (byte) (n & 0xff);
    array[2+offset] = (byte) (n >> 8 & 0xff);
    array[1+offset] = (byte) (n >> 16 & 0xff);
    array[offset] = (byte) (n >> 24 & 0xff);
  }
  public static int bytesToInt(byte b[]) {
    return  b[3] & 0xff
        | (b[2] & 0xff) << 8
        | (b[1] & 0xff) << 16
        | (b[0] & 0xff) << 24;
  }
  public static int bytesToInt(byte b[], int offset) {
    return  b[offset+3] & 0xff
        | (b[offset+2] & 0xff) << 8
        | (b[offset+1] & 0xff) << 16
        | (b[offset] & 0xff) << 24;
  }
  public static byte[] uintToBytes( long n )
  {
    byte[] b = new byte[4];
    b[3] = (byte) (n & 0xff);
    b[2] = (byte) (n >> 8 & 0xff);
    b[1] = (byte) (n >> 16 & 0xff);
    b[0] = (byte) (n >> 24 & 0xff);
    return b;
  }
  public static void uintToBytes( long n, byte[] array, int offset ){
    array[3+offset] = (byte) (n );
    array[2+offset] = (byte) (n >> 8 & 0xff);
    array[1+offset] = (byte) (n >> 16 & 0xff);
    array[offset]  = (byte) (n >> 24 & 0xff);
  }
  public static long bytesToUint(byte[] array) {
    return ((long) (array[3] & 0xff))
       | ((long) (array[2] & 0xff)) << 8
       | ((long) (array[1] & 0xff)) << 16
       | ((long) (array[0] & 0xff)) << 24;
  }
  public static long bytesToUint(byte[] array, int offset) {
    return ((long) (array[offset+3] & 0xff))
       | ((long) (array[offset+2] & 0xff)) << 8
       | ((long) (array[offset+1] & 0xff)) << 16
       | ((long) (array[offset]  & 0xff)) << 24;
  }
  public static byte[] shortToBytes(short n) {
    byte[] b = new byte[2];
    b[1] = (byte) ( n    & 0xff);
    b[0] = (byte) ((n >> 8) &aF
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