给定一个数组 A[0,1,…,n-1],请构建一个数组 B[0,1,…,n-1],其中 B 中的元素 B[i]=A[0]×A[1]×…×A[i-1]×A[i+1]×…×A[n-1]。不能使用除法。
示例:
输入: [1,2,3,4,5] 输出: [120,60,40,30,24]
解法一:dp
![](https://beijingoptbbs.oss-cn-beijing.aliyuncs.com/cs/5606289-4f182f479ea24992416a1b3f3633c910.png)
![](https://beijingoptbbs.oss-cn-beijing.aliyuncs.com/cs/5606289-ef91e8cfc54f38ad4fea129409bb4108.png)
class Solution {
public int[] constructArr(int[] a) {
if (a == null || a.length == 0) return a;
int len = a.length;
int[] left = new int[len];
int[] right = new int[len];
left[0] = right[len - 1] = 1;
for (int i = 1; i < len; i++) {
left[i] = left[i - 1] * a[i - 1];
}
for (int i = len - 2; i >= 0; i--) {
right[i] = right[i + 1] * a[i + 1];
}
int[] ans = new int[len];
for (int i = 0; i < len; i++) {
ans[i] = left[i] * right[i];
}
return ans;
}
}
![](https://beijingoptbbs.oss-cn-beijing.aliyuncs.com/cs/5606289-f5a5f09d9178a6d6f1255d8473c6dc8a.png)
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