数据来源
https://blog.csdn.net/lhxez6868/article/details/98942018?utm_medium=distribute.pc_relevant.none-task-blog-BlogCommendFromMachineLearnPai2-1.channel_param&depth_1-utm_source=distribute.pc_relevant.none-task-blog-BlogCommendFromMachineLearnPai2-1.channel_param
1查询PHP课程比c++课程成绩高的所有学生的学号
SELECT S1.SID FROM SC S1,SC S2,COURSE C1,COURSE C2 WHERE C1.CNAME='PHP' AND C2.CNAME='C++' AND S1.CID=C1.CID AND S2.CID=C2.CID AND S1.SCORE>S2.SCORE AND S1.SID =S2.SID;
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2查询名字含有’李‘的老师的个数
SELECT COUNT(TID) FROM TEACHER WHERE TNAME LIKE '李%';
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3 查询平均成绩大于70分的学生的学号以及平均分
SELECT SID, AVG(SCORE) AS T FROM SC GROUP BY SID HAVING T>70;
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4查询各科最高分和最低分
SELECT CID,MAX(SCORE),MIN(SCORE) FROM SC GROUP BY CID;
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5查询所有同学的学号、姓名、选课数、总成绩
SELECT STUDENT.SID,SNAME,COUNT(CID),SUM(SCORE) FROM STUDENT,SC WHERE STUDENT.SID=SC.SID GROUP BY STUDENT.SID;
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6查询学过“李纯”老师课的同学的学号、姓名
SELECT S.SID,SNAME FROM SC,COURSE C,STUDENT S,TEACHER T WHERE T.TNAME='李纯' AND T.TID=C.TID AND C.CID=SC.CID AND SC.SID=S.SID;
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7查询没学过“李雷”老师课的同学的学号、姓名
SELECT S.SID,SNAME FROM STUDENT S WHERE S.SID NOT IN (SELECT DISTINCT SC.SID FROM SC WHERE SC.CID IN (SELECT CID FROM TEACHER T,COURSE C WHERE T.TNAME='李雷' AND C.TID=T.TID));
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8查询学过“001”并且也学过编号“002”课程的同学的学号、姓名
SELECT S.SID,SNAME FROM STUDENT S,SC S1,SC S2 WHERE S1.CID='001' AND S2.CID='002' AND S1.SID=S2.SID AND S1.SID=S.SID;
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9查询课程编号“002”的成绩比课程编号“001”课程低的所有同学的学号、姓名
SELECT S.SID,SNAME FROM STUDENT S,SC S1,SC S2 WHERE S1.CID='001' AND S2.CID='002' AND S1.SID=S2.SID AND S1.SID=S.SID AND S1.SCORE>S2.SCORE;
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10删除学习“李纯”老师课的SC表记录
DELECT FROM SC WHERE CID IN (SELECT CID FROM TEACHER T,COURSE C WHERE C.TID=T.TID AND T.TNAME='李纯');
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11查询学过“李雷”老师所教的所有课的同学的学号、姓名
select s.sid,s.sname from student s,(
select sc.sid,count(sc.sid) from sc where sc.cid in(
select c.cid from course c,teacher t where c.tid=t.tid and tname='李雷'
)
group by sc.sid having count(sc.sid)=(
select count(*) from course c,teacher t where c.tid=t.tid and tname='李雷'
)
) t
where s.sid = t.sid
12.查询至少有一门课与学号为“1001”的同学所学相同的同学的学号和姓名
select sid,sname from student where sid in(
select sid from sc where cid in(
select cid from sc where sid = '1001'
) and sid!='1001'
)
13查询没有学全所有课的同学的学号、姓名
select s.sid,s.sname from student s,
(
select sid,count(*) from sc group by sid
having count(*)=(select count(*) from course)
) t
where s.sid=t.sid
14按各科平均成绩从低到高和及格率的百分数从高到低顺序 补充:concat() 方法用于连接两个或多个数组 百分数表示方法 CONCAT(值1/值2*100,'%')
select s1.cid,avg(s1.score) avg_sc,concat(t.c2/count(s1.score)*100,'%') rate
from sc s1 left join
(select cid cid2,count(*) c2 from sc where score>=60 group by cid) t
on s1.cid = t.cid2
group by s1.cid order by avg_sc,rate desc
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