C++遍历Lua table的方法实例

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niminba   2021-5-23 03:54   2544   0

Lua table数据如下:

复制代码 代码如下:

--$ cat test.lua lua文件
user = {
        ["name"] = "zhangsan",
        ["age"] = "22",
        ["friend"] = {
                [1] = {
                    ["name"] = "小丽",
                    ["sex"] = "女",
                    ["age"] = "20",
                },
                [2] = {
                    ["name"] = "小罗",
                    ["sex"] = "男",
                    ["age"] = "20",
                },
            },
        }

要读出上面table 中所有数据,C++代码如下:

复制代码 代码如下:

//C++代码:
#include <lua.hpp>
#include <iostream>
#include <string>
using namespace std;
 
bool popTable(lua_State* L, int idx)
{
    try{
        lua_pushnil(L);
        while(lua_next(L, idx) != 0){
            int keyType = lua_type(L, -2);
            if(keyType == LUA_TNUMBER){
                double value = lua_tonumber(L, -2);
                cout << "Key:" << value << endl;
            }else if(keyType == LUA_TSTRING){
                const char*  value = lua_tostring(L, -2);
                cout << "Key:" << value << endl;
            }else{
                cout << "Invalid key type: " << keyType << endl;
                return false;
            }
            int valueType = lua_type(L, -1);
            switch(valueType){
                case LUA_TNIL:
                {
                    cout << "Value: nil" << endl;
                    break;
                }
                case LUA_TBOOLEAN:
                {
                    int value = lua_toboolean(L, -1);
                    cout << value << endl;
                    break;
                }
                case LUA_TNUMBER:
      &}
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